NCERT Solutions for Class 10 – Complete Chapter-wise Study Material
9. Light-Reflection and Refraction is one of the most important chapters in the Class 10 Science English NCERT Solutions curriculum. This chapter plays a significant role in helping students build a strong conceptual foundation while preparing for school examinations, class tests, unit tests, half-yearly examinations, annual examinations, and CBSE board assessments. The chapter has been carefully designed according to the latest NCERT syllabus, making it an essential part of every student's study plan.
The 9. Light-Reflection and Refraction - Class 10 Science English NCERT Solutions available on ATP Education explain every question in a simple, accurate, and step-by-step manner. Each answer is prepared according to the latest CBSE guidelines so that students can understand the concepts clearly without confusion. Whether you are completing your homework, revising before examinations, or strengthening your understanding of the subject, these solutions provide reliable academic support throughout your learning journey.
One of the biggest advantages of studying 9. Light-Reflection and Refraction is that it helps students understand important concepts, definitions, examples, and textbook exercises in an organized way. Instead of memorizing answers, students learn how to develop logical thinking, improve analytical skills, and write well-structured answers in examinations. This chapter also helps improve problem-solving ability and encourages conceptual learning, which is essential for scoring higher marks in school and competitive examinations.
Our Class 10 Science NCERT Solutions cover all textbook questions, important exercise questions, and chapter-wise explanations in English Medium. Every solution is written in easy-to-understand language, allowing students to revise the chapter quickly before examinations. Regular practice of these solutions improves confidence, strengthens subject knowledge, and reduces examination stress.
Students preparing for school assessments should carefully study 9. Light-Reflection and Refraction because questions from this chapter are frequently asked in objective questions, short answer questions, long answer questions, competency-based questions, and case-study questions. Understanding the concepts explained in this chapter also helps students connect related topics from other chapters, making overall learning more effective and meaningful.
At ATP Education, we continuously update our Class 10 Science English NCERT Solutions according to the latest NCERT textbooks and CBSE curriculum. Students can confidently use these chapter-wise solutions for daily study, homework assistance, quick revision, examination preparation, and self-learning. By studying 9. Light-Reflection and Refraction thoroughly and practising every question regularly, students can strengthen their concepts, improve writing skills, and achieve better academic performance in both school and board examinations.
9. Light-Reflection and Refraction - Class 10 Science English NCERT Solutions
9. Light-Reflection and Refraction
Chapter Review
Chapter Review
- Light seems to travel in straight lines.
- The laws of reflection of light (i) The angle of incidence is equal to the angle of reflection. (ii) The incident ray, the normal to the mirror at the point of incidence and the reflected ray, all lie in the same plane.
- Image formed by a plane mirror is always virtual and erect. The size of the image is equal to that of the object.
- The reflecting surface of such mirrors can be considered to form
a part of the surface of a sphere. Such mirrors, whose reflecting surfaces are spherical, are called spherical mirrors. - A spherical mirror, whose reflecting surface is curved inwards,
that is, faces towards the centre of the sphere, is called a concave mirror. - A spherical mirror whose reflecting surface is curved outwards, is called a convex mirror.
- The centre of the reflecting surface of a spherical mirror is a point called the pole.
- The reflecting surface of a spherical mirror forms a part of a sphere.
This sphere has a centre. This point is called the centre of curvature. - The radius of the sphere of which the reflecting surface of a spherical mirror forms a part, is called the radius of curvature.
- A straight line passing through the pole and the centre of curvature of a spherical mirror. This line is called the principal axis.
- The distance between the pole and the principal focus of a spherical mirror is called the focal length.
- The diameter of the reflecting surface of spherical mirror is called its aperture.
- The nature, position and size of the image formed by a concave mirror depends on the position of the object.
- Concave mirrors are commonly used in torches, search-lights and
vehicles headlights to get powerful parallel beams of light. - Convex mirrors are commonly used as rear-view (wing) mirrors in
vehicles. - The distance of the principal focus from the pole is called the focal length.
- Light travels in vacuum with an enormous speed of 3×108 m s-1. The speed of light is different in different media.
- A ray of light travelling from a rarer medium to a denser medium slows down and bends towards the normal. When it travels from a denser medium to a rarer medium, it speeds up and bends away from the normal.
- A lens have two spherical surfaces, bulging outwards. Such a lens is called a convex lens. It is thicker at the middle as compared to the edges. Convex lens converges light rays. Hence convex lenses are called converging lenses.
- A lens have two spherical surfaces curved inwards. It is thicker at the edges than at the middle. Such lenses diverge light rays.Such lenses are called concave lens or diverging lenses.
- The SI unit of power of a lens is ‘dioptre’.
- The power of a convex lens is positive and that of a concave lens is negative.
9. Light-Reflection and Refraction
Text-book Questions
Text-book Questions
Page no. 168
Q1. Define the principal focus of a concave mirror.
Ans: The incident rays parallel to the principal axis after reflection intersect at a point F between the pole and the center of curvature of the mirror. This point is called the principal focus of a concave mirror.
Q2. The radius of curvature of a spherical mirror is 20 cm. What is its focal length?
Ans: Radius of curvature = 20 cm
Focus distance = radius of curvature/2
= 20/2
= 10 cm
Thus, the focal length of the given spherical mirror is 10 cm.
Q3. Name a mirror that can give an erect and enlarged image of an object.
Ans: A concave mirror, when the object is placed between the pole and the principal focus of the concave mirror, it forms an erect and magnified image.
Q4. Why do we prefer a convex mirror as a rear-view mirror in vehicles?
Ans: Convex mirrors are also preferred because they always produce an erect image though it is smaller. Their field of vision is also very large because they are curved outwards. Hence, convex mirrors enable the driver to see a much larger area behind him as compared to plane mirrors.
Page no. 171
Q1. Find the focal length of a convex mirror whose radius of curvature is 32 cm.
Ans: In a convex mirror,
radius of curvature R = 32 cm
radius of curvature = 2 × focus distance
Focus distance = radius of curvature/2
= 32/2
= 16 cm
Thus, the focal length of that convex mirror = 16 cm.
Q2. A concave mirror produces three times magnified (enlarged) real image of an object placed at 10 cm in front of it. Where is the image located?
Ans: In a concave mirror,
Object distance (u) = – 10 cm
Magnification (m) = – 3 [Since the image is real]
Page no. 178
Q1. A ray of light travelling in air enters obliquely into water. Does the light ray bend towards the normal or away from the normal? Why?
Ans: The ray of light will bend towards the normal, because the ray of light enters from air which is a rarer medium to water which is a denser medium than air, then in such a case the light will bend towards the normal.
Q2. Light enters from air to glass having refractive index 1.50. What is the speed of light in the glass? The speed of light in vacuum is 3 × 108 m s–1.
Answer:
Q3. Find out, from Table 10.3, the medium having highest optical density. Also find the medium with lowest optical density.
Ans: The medium of maximum optical density is diamond whose refractive index is 2.42.
The medium of minimum optical density is air whose refractive index is 1.0003.
Q4. You are given kerosene, turpentine and water. In which of these does the light travel fastest? Use the information given in Table 10.3.
Ans: From Table 10.3
Refractive index of kerosene = 1.44
Refractive index of turpentine = 1.47
Refractive index of water = 1.33
In this, the speed of light is highest in water and the speed of light is the least in turpentine oil because the higher the refractive index, the less will be the speed of light in that medium and the lower the refractive index of which is the speed of light in that medium. will be more
Q5. The refractive index of diamond is 2.42. What is the meaning of this statement?
Ans: The refractive index of diamond is 2.42. The meaning of this statement is that the optical density of diamond is high, due to which it is a hard material, it has the lowest speed of light.
Page no. 148
Q1. Define 1 dioptre of power of a lens.
Ans: If the focal length of a lens is 1 meter, then it is called 1 diopter power of the lens.
Solutions
Q2. A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the convex lens if the image is equal to the size of the object? Also, find the power of the lens.
Solution:
Given:
- Image distance, v = +50 cm
- The image is real, inverted, and equal in size to the object.
When the image formed by a convex lens is real, inverted, and equal in size to the object, the object is placed at 2F. Therefore, the image is also formed at 2F.
Hence,
- Object distance, u = –50 cm
- Image distance, v = +50 cm
Using the lens formula:
1/f = 1/v − 1/u
= 1/50 − (−1/50)
= 2/50 = 1/25
f = +25 cm = 0.25 m
Power of the lens:
P = 1/f (in metre)
P = 1/0.25 = +4 D
Answer:
- The needle is placed 50 cm in front of the lens (at 2F).
- Power of the convex lens = +4 dioptres.
Q3. Find the power of a concave lens of focal length 2 m.
Solution:
Given:
- Focal length of concave lens, f = –2 m
Power of a lens is given by:
P = 1/f
P = 1/(–2)
P = –0.5 D
Answer:
- Power of the concave lens = –0.5 dioptre.
9. Light-Reflection and Refraction
TextBook Exercise
NCERT Solutions Exercise
Q1. Which one of the following materials cannot be used to make a lens?
(a) Water (b) Glass (c) Plastic (d) Clay
Ans: (d) Clay
Q2. The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object?
(a) Between the principal focus and the centre of curvature
(b) At the centre of curvature
(c) Beyond the centre of curvature
(d) Between the pole of the mirror and its principal focus.
Ans: (a) Between the principal focus and the centre of curvature
Q3. Where should an object be placed in front of a convex lens to get a real image of the size of the object?
(a) At the principal focus of the lens
(b) At twice the focal length
(c) At infinity
(d) Between the optical centre of the lens and its principal focus.
Ans: (b) At twice the focal length
Q4. A spherical mirror and a thin spherical lens have each a focal length of –15 cm. The mirror and the lens are likely to be
(a) both concave.
(b) both convex.
(c) the mirror is concave and the lens is convex.
(d) the mirror is convex, but the lens is concave.
Ans: (a) both concave.
Q5. No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be
(a) plane.
(b) concave.
(c) convex.
(d) either plane or convex.
Ans: (d) either plane or convex.
Q6. Which of the following lenses would you prefer to use while reading small letters found in a dictionary?
(a) A convex lens of focal length 50 cm.
(b) A concave lens of focal length 50 cm.
(c) A convex lens of focal length 5 cm.
(d) A concave lens of focal length 5 cm.
Ans: (c) A convex lens of focal length 5 cm.
Q7. We wish to obtain an erect image of an object, using a concave mirror of focal length 15 cm. What should be the range of distance of the object from the mirror? What is the nature of the image? Is the image larger or smaller than the object? Draw a ray diagram to show the image formation in this case.
Answer: In a concave mirror, a virtual and erect image is formed only when the object is between the principal focus and the pole. Since the focal length of a concave mirror is 15 cm, that is, the distance between the pole and the focus is 15 cm. Therefore the object should be placed between 0cm to 15cm in front of the mirror, only then a erect image is formed.
Nature of Image : Virtual and Upright.
Image size: larger than the object.
Q8. Name the type of mirror used in the following situations.
(a) Headlights of a car.
(b) Side/rear-view mirror of a vehicle.
(c) Solar furnace. Support your answer with reason.
Ans:
(a) The head-light of a car is made of a concave mirror, because if the bulb is placed at the principal focus of the mirror, it reflects from the mirror and forms a parallel beam.
(b) A convex mirror is used for the side/rear-view mirror of a vehicle because it always produces a small but erect image. Since the convex mirror is curved outwards, its field of vision is greatly increased, so that the driver can see a large part of the rear of the vehicle.
(c) Sunlight has to be focused in a solar furnace, for which a concave mirror is suitable. This mirror passes light rays coming through infinity parallel to the principal axis through the focus, due to which the temperature around the focus increases from 1800C to 2000C.
Q9. One-half of a convex lens is covered with a black paper. Will this lens produce a complete image of the object? Verify your answer experimentally. Explain your observations.
Answer: Yes, even if half of a convex lens is covered with black paper, this lens forms a complete and clear image of a given object.
Testing - Now keep a convex lens covered in half with a black paper with the help of a stand and keep a burning candle on one side of the lens and a white curtain on the other side. In observation we find that the full image of the candle is made on the screen which is real and inverted.
Solutions
Q10. An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.
Solution:
Given:
- Object height, ho = 5 cm
- Object distance, u = –25 cm
- Focal length, f = +10 cm
Using the lens formula:
1/f = 1/v − 1/u
1/10 = 1/v + 1/25
1/v = 1/10 − 1/25 = 3/50
v = +16.7 cm
Magnification, m = v/u = 16.7/–25 = –0.67
Image height, hi = m × ho = –0.67 × 5 = –3.35 cm
Answer:
- Image distance = 16.7 cm
- Image height = 3.35 cm
- Nature: Real, inverted and diminished.
Q11. A concave lens of focal length 15 cm forms an image 10 cm from the lens. How far is the object placed from the lens? Draw the ray diagram.
Solution:
Given:
- f = –15 cm
- v = –10 cm
Using the lens formula:
1/f = 1/v − 1/u
–1/15 = –1/10 − 1/u
–1/u = –1/15 + 1/10 = 1/30
u = –30 cm
Answer:
- The object is placed 30 cm in front of the concave lens.
- The image is virtual, erect and diminished.
Q12. An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.
Solution:
Given:
- u = –10 cm
- f = +15 cm
Using the mirror formula:
1/f = 1/v + 1/u
1/15 = 1/v − 1/10
1/v = 1/15 + 1/10 = 1/6
v = +6 cm
Answer:
- Image distance = 6 cm behind the mirror.
- Nature: Virtual, erect and diminished.
Q13. The magnification produced by a plane mirror is +1. What does this mean?
Solution:
Magnification of +1 means:
- The image is of the same size as the object.
- The image is virtual and erect.
- The image is formed at the same distance behind the mirror as the object is in front of it.
Answer:
A plane mirror always forms a virtual, erect image of the same size as the object.
Q14. An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, its nature and size.
Solution:
Given:
- Object height = 5 cm
- u = –20 cm
- R = +30 cm
- f = R/2 = +15 cm
Using the mirror formula:
1/15 = 1/v − 1/20
1/v = 1/15 + 1/20 = 7/60
v = +8.57 cm
Magnification, m = –v/u = –8.57/–20 = 0.43
Image height = 0.43 × 5 = 2.15 cm
Answer:
- Image distance = 8.57 cm behind the mirror.
- Image height = 2.15 cm
- Nature: Virtual, erect and diminished.
Q15. An object of size 7.0 cm is placed at 27 cm in front of a concave mirror of focal length 18 cm. At what distance from the mirror should a screen be placed, so that a sharp focussed image can be obtained? Find the size and the nature of the image.
Solution:
Given:
- Object height = 7 cm
- u = –27 cm
- f = –18 cm
Using the mirror formula:
–1/18 = 1/v − 1/27
1/v = –1/18 + 1/27 = –1/54
v = –54 cm
Therefore, the screen should be placed 54 cm in front of the mirror.
Magnification, m = –v/u = –(–54)/(–27) = –2
Image height = –2 × 7 = –14 cm
Answer:
- Screen distance = 54 cm
- Image height = 14 cm
- Nature: Real, inverted and enlarged.
Q16. Find the focal length of a lens of power –2.0 D. What type of lens is this?
Solution:
Power, P = –2.0 D
Focal length, f = 1/P
f = 1/(–2) = –0.5 m = –50 cm
Answer:
- Focal length = –0.5 m (–50 cm)
- It is a concave (diverging) lens.
Q17. A doctor has prescribed a corrective lens of power +1.5 D. Find the focal length of the lens. Is the prescribed lens diverging or converging?
Solution:
Power, P = +1.5 D
Focal length, f = 1/P
f = 1/1.5 = 0.67 m = 66.7 cm
Answer:
- Focal length = 0.67 m (66.7 cm)
- Since the power is positive, the prescribed lens is a convex (converging) lens.
9. Light-Reflection and Refraction
Additional Questions With Solutions
Extra Important Questions with Answers – Chapter 9: Light – Reflection and Refraction
Q1: What is reflection of light?
Ans: Reflection of light is the bouncing back of light into the same medium after striking a reflecting surface.
Q2: State the two laws of reflection of light.
Ans:
- The angle of incidence is equal to the angle of reflection.
- The incident ray, reflected ray, and the normal at the point of incidence lie in the same plane.
Q3: What is refraction of light?
Ans: Refraction is the bending of light when it passes from one transparent medium to another due to a change in its speed.
Q4: Why does light bend during refraction?
Ans: Light bends because its speed changes when it travels from one medium to another having a different optical density.
Q5: Define the principal focus of a concave mirror.
Ans: The principal focus of a concave mirror is the point on its principal axis where rays parallel to the principal axis meet after reflection.
Q6: Define the principal focus of a convex mirror.
Ans: The principal focus of a convex mirror is the point behind the mirror from which rays parallel to the principal axis appear to diverge after reflection.
Q7: What is the radius of curvature of a spherical mirror?
Ans: The radius of curvature is the distance between the pole and the centre of curvature of the mirror.
Q8: What is the relationship between the focal length and radius of curvature of a spherical mirror?
Ans: The focal length is half of the radius of curvature.
Q9: What is the pole of a spherical mirror?
Ans: The pole is the geometric centre of the reflecting surface of a spherical mirror.
Q10: What is the centre of curvature?
Ans: The centre of curvature is the centre of the sphere of which the mirror is a part.
Q11: What is magnification?
Ans: Magnification is the ratio of the height of the image to the height of the object.
Q12: What does a positive magnification indicate?
Ans: Positive magnification indicates that the image is virtual and erect.
Q13: What does a negative magnification indicate?
Ans: Negative magnification indicates that the image is real and inverted.
Q14: What type of image is formed by a plane mirror?
Ans: A plane mirror forms a virtual, erect image of the same size as the object.
Q15: Name the mirror used as a rear-view mirror in vehicles. Give one reason.
Ans: A convex mirror is used because it provides a wide field of view and always forms an erect, diminished image.
Q16: Which mirror is used by dentists? Why?
Ans: Dentists use a concave mirror because it forms a magnified, erect image of nearby teeth.
Q17: What is a lens?
Ans: A lens is a transparent optical device bounded by two curved surfaces or one curved and one plane surface that refracts light.
Q18: Differentiate between a convex lens and a concave lens.
Ans:
- A convex lens is thicker at the centre and converges light rays.
- A concave lens is thinner at the centre and diverges light rays.
Q19: Why is a convex lens called a converging lens?
Ans: It is called a converging lens because it brings parallel rays of light to a single point called the principal focus.
Q20: Why is a concave lens called a diverging lens?
Ans: It is called a diverging lens because it spreads parallel rays of light after refraction.
Q21: Define the power of a lens.
Ans: The power of a lens is its ability to converge or diverge light rays. It is the reciprocal of its focal length measured in metres.
Q22: What is the SI unit of power of a lens?
Ans: The SI unit of power is the dioptre (D).
Q23: Why is the power of a convex lens positive?
Ans: The power of a convex lens is positive because its focal length is positive.
Q24: Why is the power of a concave lens negative?
Ans: The power of a concave lens is negative because its focal length is negative.
Q25: What happens to a ray passing through the optical centre of a thin lens?
Ans: The ray passes through the optical centre without any deviation.
Q26: State any two differences between reflection and refraction.
Ans:
- Reflection is the bouncing back of light, whereas refraction is the bending of light.
- Reflection occurs in the same medium, whereas refraction occurs when light passes from one medium to another.
Q27: Why are spherical mirrors preferred over plane mirrors in many applications?
Ans: Spherical mirrors can converge or diverge light rays and are capable of forming enlarged or diminished images, making them useful in vehicles, telescopes, and medical instruments.
Q28: What are the uses of a concave mirror?
Ans:
- As shaving and makeup mirrors.
- By dentists for examining teeth.
- In headlights and searchlights.
- In solar furnaces.
Q29: What are the uses of a convex mirror?
Ans:
- As rear-view mirrors in vehicles.
- For surveillance in shops and parking areas.
- At road intersections to avoid accidents.
Q30: Why is understanding reflection and refraction important in daily life?
Ans: Reflection and refraction help in the working of mirrors, lenses, cameras, microscopes, telescopes, spectacles, projectors, and many other optical devices used in everyday life.
9. Light-Reflection and Refraction
Long Additional Questions With Solutions
Long Additional Questions with Solutions – Chapter 9: Light – Reflection and Refraction
Q1. State the laws of reflection of light. Explain the formation of an image by a plane mirror with its characteristics.
Solution:
Reflection of light is the phenomenon in which light rays bounce back into the same medium after striking a reflecting surface.
Laws of Reflection:
- The angle of incidence is equal to the angle of reflection.
- The incident ray, reflected ray, and the normal at the point of incidence lie in the same plane.
Image Formation by a Plane Mirror:
- The image is formed behind the mirror.
- It is virtual and erect.
- It is of the same size as the object.
- The image is laterally inverted.
- The image is formed at the same distance behind the mirror as the object is in front of it.
Q2. Explain the formation of images by a concave mirror for different positions of the object.
Solution:
A concave mirror can produce different types of images depending on the position of the object.
- Object at Infinity: Image forms at the focus; highly diminished, real and inverted.
- Beyond Centre of Curvature (C): Image forms between C and F; diminished, real and inverted.
- At Centre of Curvature (C): Image forms at C; same size, real and inverted.
- Between C and F: Image forms beyond C; enlarged, real and inverted.
- At Focus (F): Image forms at infinity; highly enlarged.
- Between Pole (P) and Focus (F): Image forms behind the mirror; virtual, erect and enlarged.
Q3. Describe the image formation by a convex mirror. Why is it used as a rear-view mirror?
Solution:
A convex mirror always forms an image behind the mirror.
- The image is always virtual and erect.
- The image is diminished.
- It provides a wide field of view.
Reason for Use as Rear-view Mirror:
- It allows the driver to see a larger area behind the vehicle.
- The image remains erect.
- It helps reduce blind spots and improves road safety.
Q4. Explain refraction of light. Why does light bend when it passes from one medium to another?
Solution:
Refraction is the bending of light when it passes from one transparent medium to another due to a change in its speed.
When light travels from a rarer medium to a denser medium, its speed decreases and it bends towards the normal. When it travels from a denser medium to a rarer medium, its speed increases and it bends away from the normal.
Applications of Refraction:
- Formation of images by lenses.
- Working of cameras and microscopes.
- Optical fibres.
- Human eye.
Q5. Explain the structure, working and uses of a convex lens.
Solution:
A convex lens is thicker at the centre and thinner at the edges.
It converges parallel rays of light to a point called the principal focus.
Image Formation:
- Produces real and inverted images when the object is beyond the focus.
- Produces a virtual, erect and magnified image when the object is between the focus and the optical centre.
Uses:
- Magnifying glass.
- Microscopes.
- Telescopes.
- Cameras.
- Correcting hypermetropia.
Q6. Explain the structure, working and uses of a concave lens.
Solution:
A concave lens is thinner at the centre and thicker at the edges.
It diverges parallel rays of light, making them appear to originate from the principal focus.
Characteristics of Image:
- Always virtual.
- Always erect.
- Always diminished.
Uses:
- Correcting myopia.
- Door viewers (peepholes).
- Optical instruments.
Q7. What is magnification? Derive the expression for magnification produced by mirrors and lenses.
Solution:
Magnification is the ratio of the height of the image to the height of the object.
For Mirrors:
Magnification (m) = Height of Image / Height of Object = –v/u
For Lenses:
Magnification (m) = Height of Image / Height of Object = v/u
Significance:
- Positive magnification indicates a virtual and erect image.
- Negative magnification indicates a real and inverted image.
- |m| > 1 means enlarged image.
- |m| < 1 means diminished image.
Q8. Explain the concept of power of a lens. State its SI unit and significance.
Solution:
The power of a lens measures its ability to converge or diverge light rays.
It is equal to the reciprocal of the focal length (in metres).
SI Unit: Dioptre (D)
Significance:
- A convex lens has positive power.
- A concave lens has negative power.
- A lens with shorter focal length has greater power.
- Power is used in prescribing spectacles.
Q9. Differentiate between a concave mirror and a convex mirror.
Solution:
| Concave Mirror | Convex Mirror |
|---|---|
| Reflecting surface curves inward. | Reflecting surface curves outward. |
| Can form real or virtual images. | Always forms virtual images. |
| May produce enlarged images. | Always produces diminished images. |
| Used in shaving mirrors and headlights. | Used as rear-view mirrors. |
Q10. Differentiate between a convex lens and a concave lens.
Solution:
| Convex Lens | Concave Lens |
|---|---|
| Thicker at the centre. | Thinner at the centre. |
| Converges light rays. | Diverges light rays. |
| Focal length is positive. | Focal length is negative. |
| Used to correct hypermetropia. | Used to correct myopia. |
| Can form real or virtual images. | Always forms virtual, erect and diminished images. |
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Chapter Sources of Energy Solutions
Sources of Energy Open Chapters
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NCERT Solutions Class 10 Science
Chapter 13. Our Environment Solutions
13. Our Environment Open Chapters
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NCERT Solutions Class 10 Science
Chapter 16. Management of Natural Resources Solutions
16. Management of Natural Resources Open Chapters
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Class 10 NCERT Book Solutions
Chapter-wise NCERT Solutions for Class 6 to 12 prepared according to the latest CBSE syllabus.
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NCERT Solutions Class 10 Mathematics
Class 10 Mathematics Book Solutions
Mathematics Open Book
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NCERT Solutions Class 10 English First Flight
Class 10 English First Flight Book Solutions
Open Book
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NCERT Solutions Class 10 Footprints Without Feet
Class 10 Footprints Without Feet Book Solutions
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NCERT Solutions Class 10 English
Class 10 English Book Solutions
First Flight Open Book
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