NCERT Solutions for Class 6 – Complete Chapter-wise Study Material
2. Whole Numbers is one of the most important chapters in the Class 6 Mathematics English NCERT Solutions curriculum. This chapter plays a significant role in helping students build a strong conceptual foundation while preparing for school examinations, class tests, unit tests, half-yearly examinations, annual examinations, and CBSE board assessments. The chapter has been carefully designed according to the latest NCERT syllabus, making it an essential part of every student's study plan.
The 2. Whole Numbers - Class 6 Mathematics English NCERT Solutions available on ATP Education explain every question in a simple, accurate, and step-by-step manner. Each answer is prepared according to the latest CBSE guidelines so that students can understand the concepts clearly without confusion. Whether you are completing your homework, revising before examinations, or strengthening your understanding of the subject, these solutions provide reliable academic support throughout your learning journey.
One of the biggest advantages of studying 2. Whole Numbers is that it helps students understand important concepts, definitions, examples, and textbook exercises in an organized way. Instead of memorizing answers, students learn how to develop logical thinking, improve analytical skills, and write well-structured answers in examinations. This chapter also helps improve problem-solving ability and encourages conceptual learning, which is essential for scoring higher marks in school and competitive examinations.
Our Class 6 Mathematics NCERT Solutions cover all textbook questions, important exercise questions, and chapter-wise explanations in English Medium. Every solution is written in easy-to-understand language, allowing students to revise the chapter quickly before examinations. Regular practice of these solutions improves confidence, strengthens subject knowledge, and reduces examination stress.
Students preparing for school assessments should carefully study 2. Whole Numbers because questions from this chapter are frequently asked in objective questions, short answer questions, long answer questions, competency-based questions, and case-study questions. Understanding the concepts explained in this chapter also helps students connect related topics from other chapters, making overall learning more effective and meaningful.
At ATP Education, we continuously update our Class 6 Mathematics English NCERT Solutions according to the latest NCERT textbooks and CBSE curriculum. Students can confidently use these chapter-wise solutions for daily study, homework assistance, quick revision, examination preparation, and self-learning. By studying 2. Whole Numbers thoroughly and practising every question regularly, students can strengthen their concepts, improve writing skills, and achieve better academic performance in both school and board examinations.
2. Whole Numbers - Class 6 Mathematics English NCERT Solutions
2. Whole Numbers
Exercise 2.1
Exercise-2.1
1. Write the next three natural numbers after 10999.
Solution:
The next three natural number after 10999 are:
10999+1, 10999+2, 10999+3
i.e. 11000, 11001, 11002
2. Write the three whole numbers occurring just before 10001.
Solution:
The next three natural number after 10999 are:
10999+1, 10999+2, 10999+3
i.e. 11000, 11001, 11002
3. Which is the smallest whole number?
Solution: 0 is the smallest whole number.
4. How many whole numbers are there between 32 and 53?
Solution:
there are (53 - 32) - 1 = 21 - 1 = 20
whole numbers between 32 and 53 are 20.
5. Write the successor of :
(a) 2440701 (b) 100199 (c) 1099999 (d) 2345670
(a) 2440701
Solution: 2440701 + 1 = 2440702
(b) 100199
Solution: 100199 + 1 = 100200
(C) 1099999
Solution: 1099999 + 1 = 1100000
(d) 2345670
Solution: 2345670 + 1 = 2345671
6. Write the predecessor of :
(a) 94 (b) 10000 (c) 208090 (d) 7654321
(a) 94
Solution: 94 - 1= 93
(b) 10000
Solution: 10000 – 1= 9999
(c) 208090
Solution: 208090 – 1= 208089
(d) 7654321
Solution: 7654321 – 1= 7654320
7. In each of the following pairs of numbers, state which whole number is on the left of the other number on the number line. Also write them with the appropriate sign (>, <) between them.
(a) 530, 503
(b) 370, 307
(c) 98765, 56789
(d) 9830415, 10023001
(a) 530, 503
Solution: Here, 503 lies on the left of the 530 on number line
Therefore, 530 > 503 or 503<530
(b) 370,307
Solution: Here, 307 lies on the left of the 370 on number line
Therefore, 307<370 or 370>307
(c) 98765, 56789
Solution: Here, 56789 lies on the left of the 98765 on number line
Therefore, 56789 < 98765 or98765 > 56789
(d) 9830415, 10023001
Solution: Here, Here, 10023001 lie on the left of the 9830415on number line
Therefore, 9830415<0023001 or 9830415>10023001
8. Which of the following statements are true (T) and which are false (F) ?
(a) Zero is the smallest natural number.
(b) 400 is the predecessor of 399.
(c) Zero is the smallest whole number.
(d) 600 is the successor of 599.
(e) All natural numbers are whole numbers.
(f ) All whole numbers are natural numbers.
(g) The predecessor of a two digit number is never a single digit number.
(h) 1 is the smallest whole number.
(i) The natural number 1 has no predecessor.
(j) The whole number 1 has no predecessor.
(k) The whole number 13 lies between 11 and 12.
(l) The whole number 0 has no predecessor.
(m) The successor of a two digit number is always a two digit number.
Answer :
(a) Fallse
(b) False
(c) True
(d) True
(e) True
(f) False
(g) False
(h) False
(i) True
(j) False
(k) False
(l) True
(m) False
2. Whole Numbers
Exercise 2.2
Exercise-2.2
Q1. Find the sum by suitable rearrangement:
(a) 837 + 208 + 363
Solution: 837 + 208 + 363
= (837 + 208) + 363
= 1045 + 363
= 1408
Or Second Method
= 837 + 363 + 208
= (837 + 363) + 208
= 1200 + 208
= 1408
(b) 1962 + 453 + 1538 + 647
Solution: 1962 + 453 + 1538 + 6477
= (1962 + 453) + (1538 + 647)
= 2415 + 2185
= 4600
Or Second Method
= 1962 + 453 + 1538 + 6477
= (1538 + 1962) + (453 + 647)
= 3500 + 1100
= 4600
Q2. Find the product by suitable rearrangement:
(a) 2 × 1768 × 50
(b) 4 × 166 × 25
(c) 8 × 291 × 125
(d) 625 × 279 × 16
(e) 285 × 5 × 60
(f) 125 × 40 × 8 × 25
Solution:
(a) 2 x 1768 x 50
Solution:
2 x 50 x 1768
= (2 x 50) x 1768
= 100 x 1768
= 176800
(b) 4 x 166 x 25
Solution:
4 x 25 x 166
= (4 x 25) x 166
= 100 x 166
= 16600
(c) 8 x 291 x 125
Solution:
8 x 125 x 291
= 1000 x 291`
= 291000
(d) 125 x 40 x 8 x 25
Solution:
125 x 8 x 40 x 25
= (125 x 8) x (40 x 25)
= 1000 x 1000
= 1000000
(e) 285 × 5 × 60
Solution:
285 × 5 × 60
= 285 × (5 × 60)
= 285 × 300
= 85500
(f) 125 × 40 × 8 × 25
Solution:
125 × 40 × 8 × 25
= (125 × 8) × (40 × 25)
= 1000 × 1000
= 1000000
Q3. Find the value of the following:
(a) 297 × 17 + 297 × 3
Solution:
297 x (17 + 3)
= 297 x 20
= 5940
(b) 54279 × 92 + 8 × 54279
Solution:
54279 x (92 + 8)
= 54279 x 100
= 5427900
(c) 81265 × 169 – 81265 × 69
Solution:
81265 × 169 – 81265 × 69
= 81265 (169 – 69)
= 81265 (100)
= 8126500
(d) 3845 × 5 × 782 + 769 × 25 × 218
Solution:
3845 × 5 × 782 + 769 × 25 × 218
= 3845 × 5 × 782 + 769 × 5 × 5 × 218
= 3845 × 5 × 782 + 3845 × 5 × 218
= 3845 × 5 (782 + 218)
= 19225 × 1000
= 19225000
Q4. Find the product using suitable properties.
(a) 738 × 103
(b) 854 × 102
(c) 258 × 1008
(d) 1005 × 168
Solution:
(a) 738 × 103
= 738 (100 + 3)
= 738 × 100 + 738 × 3
= 73800 + 2214
= 76014
Solution:
(b) 854 × 102
= 854(100 + 2)
= 854 × 100 + 854 × 2
= 85400 + 1708
= 87108
Solution:
(c) 258 × 1008
= 258(1000 + 8)
= 258 × 1000 + 258 × 8
= 258000 + 2064
= 260064
Solution:
(d) 1005 × 168
= (1000 + 5) x 168
= 1000 x 168 + 5 x 168
= 168000 + 840
= 168840
5. A taxidriver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs Rs 44 per litre, how much did he spend in all on petrol?
Solution: Taxi driver filled his car petrol tank on Monday = 40 L
He filled the petrol tank on Tuesday = 50 L
The petrol costs per liter = 44 Rs
He spend in all on petrol = (40 + 50) x 44
= 90 x 44
= 3960 Rs
6. A vendor supplies 32 liters of milk to a hotel in the morning and 68 liters of milk in the evening. If the milk costs Rs 15 per liter, how much money is due to the vendor per day?
Solution: A vendor supplies milk to a hotel in the morning = 32 liters
=> A vendor supplies milk to a hotel in the evening = 68 liters
=> The cost of milk per liter = Rs 15
7. Match the following:
Solution:
(i) ----------- (c)
(ii) ---------- (a)
(iii) ---------- (b)
2. Whole Numbers
Exercise 2.3
Exercise-2.3
Q1. Which of the following will not represent zero:
(a) 1 + 0 (b) 0 × 0 (c) 0/2 (d) 10 -10/2
Solution:
(a) 1 + 0 = 1
So, it is not represent zero
(b) 0 × 0 = 0
it is represent zero
(c) 0/2 = 0
it is represent zero

Q2. If the product of two whole numbers is zero, can we say that one or both of them will be zero? Justify through examples.
Solution:
Yes, we know that the product of any whole numbers with zero is always zero.

Q3. If the product of two whole numbers is 1, can we say that one or both of them will be 1? Justify through examples.
Solution:
If only one number be 1 then the product cannot be 1.
Examples:

Here we see that one of two is 1 then product will be always second number.
If both numbers are 1, then the product is 1
Q4. Find using distributive property :
(a) 728 × 101 (b) 5437 × 1001 (c) 824 × 25 (d) 4275 × 125 (e) 504 × 35
Solution:
(a) 728 × 101
= 728(100 + 1)
= 728 × 100 + 728 × 1
= 72800 + 728
= 73528
Solution:
(b) 5437 × 1001
= 5437(1000 + 1)
= 5437 × 1000 + 5437 × 1
= 5437000 + 5437
= 5442437
Solution:
(c) 824 × 25
= 824(20 + 5)
= 824 × 20 + 824 × 5
= 16480 + 4120
= 20600
Solution:
(d) 4275 × 125
= 4275(100 + 20 + 5)
= 4275 × 100 + 4275 × 20 + 4275 × 5
= 427500 + 85500 + 21375
= 534375
Solution:
(e) 504 × 35
= (500 + 4) × 35
= 500 × 35 + 4 × 35
= 17500 + 140
= 17640
Q5. Study the pattern :
1 × 8 + 1 = 9 1234 × 8 + 4 = 9876
12 × 8 + 2 = 98 12345 × 8 + 5 = 98765
123 × 8 + 3 = 987
Write the next two steps. Can you say how the pattern works?
(Hint: 12345 = 11111 + 1111 + 111 + 11 + 1).

Mathematics
Class 6 (English Medium)
NCERT Mathematics Textbook
Chapter-wise NCERT Solutions for Class 6 to 12 prepared according to the latest CBSE syllabus.
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NCERT Solutions Class 6 Mathematics
Chapter 1. Knowing Our Numbers Solutions
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Chapter 2. Whole Numbers Solutions
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